(x^2-25)/(3x)*(24)/(2x-10)

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Solution for (x^2-25)/(3x)*(24)/(2x-10) equation: 


D( x )

3*x = 0

2*x-10 = 0

3*x = 0

3*x = 0

3*x = 0 // : 3

x = 0

2*x-10 = 0

2*x-10 = 0

2*x-10 = 0 // + 10

2*x = 10 // : 2

x = 10/2

x = 5

x in (-oo:0) U (0:5) U (5:+oo)

(24*((x^2-25)/(3*x)))/(2*x-10) = 0

(24*(x^2-25))/(3*x*(2*x-10)) = 0

( 24 )

24 = 0

x belongs to the empty set

( x^2-25 )

1*x^2 = 25 // : 1

x^2 = 25

x^2 = 25 // ^ 1/2

abs(x) = 5

x = 5 or x = -5

x in { 5} 

x = -5

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